Second Equation of Motion


 
 
Concept Explanation
 

Second Equation of Motion

SECOND EQUATION OF MOTION:

large s=ut+frac{1}{2}at^{2}

Displacement = initial velocity large times large frac{1}{2}  large times acceleration large times  large time;interval^{2}

Distance travelled = average velocity large times time = large left ( frac{Initial;velocity+final;velocity}{2} right )times time

    or   large s=frac{u+v}{2}times t

But from eq. (1), v = u + at

        large therefore   large s=frac{u+(u+at)}{2}times t      or     large s=frac{2u+at}{2}times t

    or   large s=ut+frac{1}{2}at^{2}

Sample Questions
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Question : 1

A body is dropped from the top of a tower. If its average velocity , when it reaches the ground ,  is   large 20m/sec and the time taken by it to reach the ground is 2sec  ;  the height of the tower is _______________ m.

Right Option : A
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Question : 2

IF a car at rest accelerates uniformly to a speed of 72 km/h in 10 sec.,it covers a distance of

Right Option : B
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Question : 3

A racing car has a uniform acceleration of 4m/s^2. What distance will it cover in 10s after the start from the rest.

Right Option : A
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Explanation
 
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